Balance the following by the method of half reactions and give the correct coefficients: ___[Fe(CN)6]3- + ___N2H4 + ___OH- --> ___[Fe(CN)6]4- + ___N2 + ___H2O

Answer

To balance the redox reaction using the half-reaction method in a basic solution: 1. Identify the half-reactions. Reduction: [Fe(CN)6]3- + e- --> [Fe(CN)6]4-. Oxidation: N2H4 --> N2 + 4H+ + 4e-. 2. Balance the oxidation half-reaction for basic conditions. Since it occurs in a basic solution, add 4 OH- to both sides to neutralize the H+: N2H4 + 4 OH- --> N2 + 4 H2O + 4e-. 3. Equalize electrons. Multiply the reduction half-reaction by 4 so it also involves 4 electrons: 4 [Fe(CN)6]3- + 4e- --> 4 [Fe(CN)6]4-. 4. Combine the half-reactions and cancel the electrons: 4 [Fe(CN)6]3- + N2H4 + 4 OH- --> 4 [Fe(CN)6]4- + N2 + 4 H2O. The resulting coefficients are (4, 1, 4; 4, 1, 4).