Tin (Sn) exists in the earth's crust as SnO2. Calculate the percent composition by mass of Sn and O in SnO2.

Answer

To find the percent composition by mass of Tin (Sn) and Oxygen (O) in Tin(IV) oxide (SnO2), follow these steps: 1. Find the atomic masses of the elements from the periodic table: Atomic mass of Tin (Sn) ≈ 118.71 amu, Atomic mass of Oxygen (O) ≈ 16.00 amu. 2. Calculate the total molar mass of the compound SnO2: There is 1 atom of Sn and 2 atoms of O. Total Mass = (1 * 118.71) + (2 * 16.00) = 118.71 + 32.00 = 150.71 g/mol. 3. Calculate the percentage of Tin (Sn): %Sn = (Mass of Sn / Total Mass) * 100 = (118.71 / 150.71) * 100 ≈ 78.77%. 4. Calculate the percentage of Oxygen (O): %O = (Total Mass of O / Total Mass) * 100 = (32.00 / 150.71) * 100 ≈ 21.23%. Therefore, the percent composition is 78.77% Sn and 21.23% O.