9 - 3 ÷ \frac{1}{3} + 1 = ?

Answer

To solve the expression \(9 - 3 \div \frac{1}{3} + 1\), we need to follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)). 1. Start with the division: \(3 \div \frac{1}{3}\) which is equivalent to multiplication by the reciprocal of \(\frac{1}{3}\). \[ 3 \div \frac{1}{3} = 3 \times 3 = 9 \] 2. Now substitute back into the equation: \[ 9 - 9 + 1 \] 3. Next, perform the subtraction: \(9 - 9 = 0\). 4. Finally, add 1: \[ 0 + 1 = 1 \] Therefore, the final solution is \(1\).