The provided image contains 7 multi-part chemistry and physics word problems regarding significant figures, units of measurement, and unit conversions. Topics include determining the number of significant figures, performing arithmetic operations with respect to significant figures, unit conversions for height, weight, speed, distance (light years), density, and estimating the count of atoms based on diameter.

Answer
1) Significant Figures: a. 4867 mi (4 sig figs: all non-zeroes), b. 56 mL (2 sig figs: all non-zeroes), c. 60,104 tons (5 sig figs: zeroes between non-zero digits are significant), d. 2900 g (2 sig figs: trailing zeroes without a decimal point are not significant), e. 40.2 g/cm^3 (3 sig figs), f. 0.0000003 cm (1 sig fig: leading zeroes are never significant), g. 0.7 min (1 sig fig), h. 4.6 x 10^19 atoms (2 sig figs: only the coefficient matters). 2) Operations: a. 5.6792 + 0.6 + 4.33 = 10.6092 -> 10.6 m (addition/subtraction is limited by the least precise decimal place, which is tenths). b. 3.70 - 2.9133 = 0.7867 -> 0.79 g (hundredths place). c. 4.51 x 3.6666 = 16.536366 -> 16.5 cm^2 (multiplication is limited by the least number of sig figs, which is 3). d. (3e4 + 6.827) / (0.043 - 0.021) = 30006.827 / 0.022 = 1,363,946.68 -> 1 x 10^6 (denominator has 2 sig figs, but the numerator 3e4 is ambiguous; assuming it's 1 sig fig, the answer is 1e6). 3) Conversion: Height: 6.0 ft * (1 m / 3.28 ft) = 1.8 m. Weight: 168 lb * (453.6 g / 1 lb) * (1 kg / 1000 g) = 76.2 kg. 4) Speed: 62 m/s * (1 km / 1000 m) * (0.6214 mi / 1 km) * (3600 s / 1 hr) = 138.82 -> 1.4 x 10^2 mph (2 sig figs based on 62 m/s). 5) Conversions: a. 1.42 ly * (365 days / 1 yr) * (24 hr / 1 day) * (3600 s / 1 hr) * (3.00e8 m / s) * (1 km / 1000 m) * (0.6214 mi / 1 km) = 8.35 x 10^12 miles. b. 32.4 yd * (3 ft / 1 yd) * (1 m / 3.28 ft) * (100 cm / 1 m) = 2963.4 -> 2.96 x 10^3 cm. c. 3.0e10 cm/s * (1 m / 100 cm) * (3.28 ft / 1 m) = 9.84 x 10^8 ft/s. 6) Density: Volume displacement = 260.5 mL - 242.0 mL = 18.5 mL. Density = Mass / Volume = 194.3 g / 18.5 mL = 10.5027 -> 10.5 g/mL. 7) Atoms: Diameter = 1e2 pm = 100 pm. Convert cm to pm: 1 cm = 1e10 pm. Number of atoms = Total distance / diameter = 1e10 pm / 100 pm = 1 x 10^8 atoms.