A street artist makes a painting of the architecture in a city. The artist uses a square canvas. The area of the canvas is 11 square meters. (A = s^2 and P = 4s). What is an approximation of the perimeter to the nearest meter? (sqrt(11) approx 3.3). P approx [ ] meters
![A street artist makes a painting of the architecture in a city. The artist uses a square canvas. The area of the canvas is 11 square meters. (A = s^2 and P = 4s). What is an approximation of the perimeter to the nearest meter? (sqrt(11) approx 3.3). P approx [ ] meters](https://media.hwhelper.com/ba4ce6b2-53c7-41cd-bb8b-be6a35376d85-compressed.jpg)
Answer
To find the perimeter of the square canvas, we first need to find the side length s. The area A is given as 11 square meters, and the formula for the area of a square is A = s^2. Therefore, s^2 = 11, which means the side length is s = sqrt(11). The perimeter P of a square is given by the formula P = 4s. Substituting the side length into the perimeter formula gives P = 4 * sqrt(11). The problem provides the approximation sqrt(11) approx 3.3. Substituting this into our perimeter expression, we get P approx 4 * 3.3 = 13.2 meters. Rounding to the nearest meter, we get 13 meters.