Step 4 of 7: Determine the upper class boundary for the second class.

Answer

To find the upper class boundary for a specific class in a frequency distribution table with integer class limits, you calculate the midpoint between the upper limit of that class and the lower limit of the next class. In this problem, the second class is '1176–1235' and the third class is '1236–1295'. The upper limit of the second class is 1235, and the lower limit of the third class is 1236. The upper class boundary is calculated as (1235 + 1236) / 2 = 1235.5. Therefore, the upper class boundary for the second class is 1235.5.